Question

From each of the two opposite corners of a square of side 8 cm, a quadrant of a
circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from
22
the centre as shown in fig. Find the area of the shaded portion. (Use n=
7
.).
1​

Answer 1

Answer:

Here a=8cm

Here a=8cm ⇒ Area of square =a

Here a=8cm ⇒ Area of square =a =(8)

Here a=8cm ⇒ Area of square =a =(8) =64cm

Here a=8cm ⇒ Area of square =a =(8) =64cm ⇒ Here radius of circle R=4.2cm

Here a=8cm ⇒ Area of square =a =(8) =64cm ⇒ Here radius of circle R=4.2cm⇒ Area of of circle =πR

=722×(4.2) 2

=722×(4.2) 2∴ Area of of circle =55.44cm

⇒ Radius of sector r=1.4cm and θ=90

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2×

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2×

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 7

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4)

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4)

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4) ∴ Area of 2 sectors =3.08cm

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4) ∴ Area of 2 sectors =3.08cm ⇒ Area of shaded region = Area of square - ( Area of circle +Area of 2 sectors)

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4) ∴ Area of 2 sectors =3.08cm ⇒ Area of shaded region = Area of square - ( Area of circle +Area of 2 sectors)⇒ Area of shaded region =64−(55.44+3.08)

⇒ Radius of sector r=1.4cm and θ=90 ⇒ Area of 2 sectors =2× 360 θ πr ⇒ Area of 2 sectors =2× 360 90 × 722×(1.4) ∴ Area of 2 sectors =3.08cm ⇒ Area of shaded region = Area of square - ( Area of circle +Area of 2 sectors)⇒ Area of shaded region =64−(55.44+3.08)∴ Area of shaded region =64−58.52=5.48cm

Step-by-step explanation:

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