Question

From each vertex of trapezium a sector of radius 7 cm has been cut off.
Write the total area cut off.I need the answer quickly as i was revising for board exam

Answer 1

The total area cut off is $\mathbf{154 \ (cm^{2})}$

Step-by-step explanation:

•  Given data

          Figure is given that ABCD is a trapezium.

          We know that

          $\mathbf{\angle A+\angle B+\angle C+\angle D=360^{\circ}}$

•   Each cot on corner of trapezium is sector of circle with equal radius                

           of 7 cm.

          So total angle subtend on centre of circle is 360°.

          It will make complete circle means full circle.

•   So area of circle

          $\mathbf{\textrm{Area of circle}=\pi R^{2} }$

          $\mathbf{\textrm{Area of circle}=\frac{22}{7}\times 7^{2} }$

          $\mathbf{\textrm{Area of circle}=22\times 7 }$

          $\mathbf{\textrm{Area of circle}=154 \ (cm^{2}) }$