from external point P of a circle with centre O , two tangents PQ and PR are drawn such that angle QPR is 120° , prove that 2PQ = PO
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From external point P of a circle with centre O , two tangents PQ and PR are drawn such that angle QPR is 120° , prove that 2PQ = PPO.
Given ∠QPR=120°
Radius is perpendicular to the tangent at the point of contact.
∴∠OQP=90°⇒∠QPO=60°
(tangent drawn to a circle from an external point are equally inclined to the segment, joining the center to that point).
In ΔQPO,cos60°
=
PO
PQ
⇒
2
1
=
PO
PQ
⇒2PQ=PO
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