Question

from external point PA and PB are two tangents with the circle if angle PAB = 50 degree then find angle AOB​

Answer 1

Answer:

angle pa =qa there might be something special

Answer 2

Answer:

in ∆pab given that

angle PAB is 50°

and angle PAO=90°

PAO= angle PAB+OAB

90=50+OAB

then angle OAB=40°

NOW In trianlge OAB

OA=OB

THUS angle OAB and oba will be equal

then in triangle OAB

OAB+oba+ aob =180

40+40+aob=180

aob=180+80

aob=100°