Question

From Fig. 8.33, calculate the current flowing in
each resistor.
​

Answer 1

since they are in series

therefore current divides

current through =i1

=V/r1

=9/2

=4.5ampere

current through r2+r3=

1/r1+1/r2

=1/4+1/6

=6+4/24

=10/24

=5/12ohm

i2=V/r2+r3

=9*12/5

=108/5ampere or 21.6ampere

current through 0.6 ohm resister=

i3=V/0.6

=9/0.6

=90/6

=15ampere