Question

from figure AB=8,CD=7,BD=4 find A(∆ADC)
A(∆ADB)​

Answer 1

Answer:

in triangle ABD =1/2 ×b×h

1/2×4×8

=16

in triangle abc

1 by 2 into base into height

1 by 2 into 8 into (7+4)

=44 so area of triangle adc = area of triangle abc minus area of triangle abd

=44-16=28