From figure. seg PQ|| side BC,AP=x+3,PB=x-3,AQ=x+5,QC=x-2. Find the value of x
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Answer:
Explanation:
Since PQ∥BC,
Thus using Basic Proportionality Theorem
QC
AQ
=
PB
AP
⇒
x
5
=
6
3
⇒3x=30, cross multiply
∴x=10
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