Physics, asked by reshamane153, 1 month ago

From Figure the distance travelled in 5 second is​

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Answered by moonsarkar947
0

Answer:

50m

Explanation:

Distance travelled in 5 sec = Area under vt graph

 \frac{1}{2} (1)(10) + 1(10) + 1(10) +  \frac{1}{2}(1)(10) +  \frac{1}{2}  (2)(20)

 = 5 + 10 + 10 + 5 + 20

 = 50m

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