from following figure prove that AB>CD
Attachments:
Answers
Answered by
6
to prove - AB > CD
PROOF -
IN ΔABC
AB =AC
∴∠ABC =∠ACB =70° -------1. (ANGLE OPP. TO EQUAL SIDES)
IN ΔACD
∠ACB =∠CAD +∠ADC (EXTERIOR ANGLE PROPERTY)
∠CAD = 70° -40°
∠CAD = 30° ---------2.
FROM 1 AND 2
∠CAD < ∠ACB
CD<AB (SIDE OPP. TO GREATER ANGLE IS GREATER)
PROOF -
IN ΔABC
AB =AC
∴∠ABC =∠ACB =70° -------1. (ANGLE OPP. TO EQUAL SIDES)
IN ΔACD
∠ACB =∠CAD +∠ADC (EXTERIOR ANGLE PROPERTY)
∠CAD = 70° -40°
∠CAD = 30° ---------2.
FROM 1 AND 2
∠CAD < ∠ACB
CD<AB (SIDE OPP. TO GREATER ANGLE IS GREATER)
Similar questions