from Geometry please answer, answer will mark as brainliest
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given ∆PDQ=∆PDR
PT=TD
From∆PDN This the mid point of PD
PM=MN........(1)
from∆ QRMD is the mid point
MN=NR........(2) now,
PM=PR/3
PM/PR=1/3
PT=TD
From∆PDN This the mid point of PD
PM=MN........(1)
from∆ QRMD is the mid point
MN=NR........(2) now,
PM=PR/3
PM/PR=1/3
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