Question

From given figure, In ∆ ABC, AB⊥ BC, AB =BC, AC = 2√2 then
Ɩ (AB) ​

Answer 1

Answer:

AB=BC  [Given]

ΔABC is an Isoceles triangle.

∠A≅∠C    [Isoceles triangle theorem]

∴∠A=∠C=45°

ΔABC is a 45°-45°-90° triangle.

As we know,∫(AB)=$\frac{1}{\sqrt 2}$ × AC   [Side opposite to 45° is half the hypotenuse]

                   ∫(AB)=$\frac{1}{\sqrt 2}$ × 2√2

               ∴   ∫(AB) =2 .

                     

Step-by-step explanation: I HOPE THIS HELPS YOU :)

Answer 2

AB=BC  [Given]

ΔABC is an Isoceles triangle.

∠A≅∠C    [Isoceles triangle theorem]

∴∠A=∠C=45°

ΔABC is a 45°-45°-90° triangle.

As we know,∫(AB)= × AC   [Side opposite to 45° is half the hypotenuse]

                  ∫(AB)= × 2√2

              ∴   ∫(AB) =2 .

                     

Step-by-step explanation: I HOPE THIS HELPS YOU :)