Question

from her window a girl drops a water filled balloon to the ground 6m below. fint time taken to reach the ground

pls answer this ASAP
thank you​

Answer 1

initial velocity = 0

distance = 6 m

acceleration = 9.8 m/s (due to gravity)

time = ?

s = ut + 1/2aT^2

6 = 0*t + 1/2*9.8*t^2

6 = 4.9t^2

t^2 = 6/4.9

t = under root 1.22

t = time = 1.104 seconds (aproxx)

Answer 2

Answer:-

Given:-

Height of the initial position to the final position = 6 metres

Acceleration due to gravity = + 10 m/s² [Downward]

Initial velocity (u) = 0 m/s

To Find: Time taken by the water balloon to reach the ground.

We know,

h = ut + ½gt²

where,

• h = Height,
• u = Initial velocity of the particle,
• g = Acceleration due to gravity &
• t = Time taken.

But here,

h = ½gt² (Because u = 0 m/s; 0 × t = 0)

∴ ½(10 m/s²)t² = 6 m

→ (5 m/s²)t² = 6 m

→ t² = (6 m)/(5 m/s²)

→ t² = 6/5 s²

→ t = √6/5 × √s²

→ t = 1.095 s

∴ The balloon will take approximately 1 second to reach the ground.