Question

From his house Shyam drives his car 16 km north for 7 minutes. He stops for 10minutes
to pick Madhu from her class. Then he drives 12 km east in 8 minutes. What was the
magnitude of his average velocity?

Answer 1

Answer:

Explanation:

so magnitude of displacement is (16^2+12^2)^1/2

dispalcement=20

total time=7+10+8=25min

average velocity=displacement/total time

                           =20/25

                           =0.8km/min

change the unit if required    

Answer 2

The magnitude of his average velocity is 67.2 km/h or 1.12 km/min.

Given,

Shyam drives his car 16 km north for 7 minutes.

He stops for 10 minutes to pick Madhu up from her class.

Then he drives 12 km east in 8 minutes.

To Find,

The magnitude of average velocity

Solution,

1st Lap → 16 km in 7 minutes (North)

2nd Lap → 0 km in 10 minutes

3rd Lap → 12 km in 8 minutes (East)

Since, we have to find the only magnitude, let us forget about the direction

Magnitude of average velocity = Average speed

Average Velocity = $\frac{Total Distance}{Total Time}$

Total Distance = Distance covered in Lap 1 + Distance covered in Lap 2 + Distance covered in Lap 3

Total Distance = 16 km + 0 km + 12 km

Total Distance = 28 km

Total Time = Time taken in Lap 1 + Time taken in Lap 2 + Time taken in Lap 3

Total Time = 7 min + 10 min + 8 min

Total Time = 25 min

Let us convert the time taken into hours (since it is a standard form)

25 min → $\frac{25}{60}$ hours

25 min → $\frac{5}{12}$ hours

Average Velocity = $\frac{28}{\frac{5}{12} }$

Average Velocity = $\frac{28*12}{5 }$

Average Velocity = $\frac{336}{5 }$

Average Velocity = 67.2 km/h or 1.12 km/min

Thus, the magnitude of his average velocity is 67.2 km/h or 1.12 km/min.

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