Question

From intensity distribution for a single slit, find out the conditions for maxima and minima Graphically explain the positions of secondary maxima.​

Answer 1

Answer:

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Answer 2

The intensity distribution for a single slit :

Explanation:

The conditions for maxima in the interference pattern :

1) Phase difference : δ = 2nπ

2) Path difference : Δx = nλ

The conditions for minima in the interference pattern :

1) Phase difference : $\delta = (n-\frac{1}{2} ) 2\pi$

2) Path difference : Δx = $(n-\frac{1}{2} )\lambda$

The conditions for maxima in the diffraction pattern :

1) Phase difference : $\delta = (n-\frac{1}{2} ) 2\pi$

2) Path difference : Δx = $(n-\frac{1}{2} )\lambda$

The conditions for minima in the diffraction pattern :

1) Phase difference : δ = 2nπ

2) Path difference : Δx = nλ

Secondary maxima:

Secondary maxima in the diffraction pattern due to a single slit is formed at the condition

asinθ = (2n-1)$\frac{\lambda}{2}$

Refer the following fig: