Question

From long experience it is found that the daily number of absentees in a factory follows Poisson distribution with mean 5. Find the probability that during a particular day (i) there is no absentee (ii) there are more than 5 absentees.​

Answer 1

Answer:

By using Poisson distribution,

P(x;μ)=

x!

e

−μ

μ

x

μ: The mean number of successes that occur in a specified region(parameter)

x: The actual number of successes that occur in a specified region.

P(x; μ): The Poisson probability that exactly x successes occur in a Poisson experiment, when the mean number of successes is μ

Here,μ = 2

x = 2 (exact 2 workers)

P(2;2)=

2!

e

−2

2

2