Question

From natural numbers from 9 to 1000, how many numbers are divisible by 3 ?

Answer 1

Answer:

331

Step-by-step explanation:

first term = a = 9

last term = 999

common difference = d = 3

number of terms = an = a + (n-1)d

999 = 9 + (n - 1) (3)

999 - 9 = (n-1) (3)

990 = (n-1)(3)

n - 1 = 990/3

n - 1 = 330

n = 330 + 1

n = 331

therefore the number of terms divisible by 3 from 9 to 1000 are 331

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Answer 2

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