Question

from numbers 4, -2, 2, 0, 3 find the zeros of the polynomial p(x) =x2 -2x​

Answer 1

Step-by-step explanation:

p(4)=4²-2×4

p(4)=8

p(-2)=-2²-2×-2

p(-2)=0

p(2)=2²-2×2

p(2)=0

p(0)=0

p(3)=3²-2×3

p(3)=9-6

p(3)=3