Question

from our village people started migrating to nearby cities due to unemployment the population of the village 2 years ago was 6000 if its present population is 5415 find the rate at which the migration is taking place

Answer 1

Answer:   5%

Step-by-step explanation:

• Suppose, rate at which migration is taking place is x%

• Two years ago, population was 6,000.
• we know that migration is x% i.e  0.01(x)

hence, population migrated is 6000[0.01(x)]

Now, population left last year would be

6000 - 6000[0.01(x)]⇒ 6000[ 1- (0.01)x ]

For simplicity, suppose this equation as y

Hence, 6000[ 1- (0.01)x ] = y

Population migrated this year is again x% i.e. 0.01 x

population left this year i.e. present population is

y - y (0.01) x

but acc' to our question, present population is 5415.

hence, y[ 1- x(0.01)] = 5415

substituting value of y we get,

6000[ 1- (0.01)x ][ 1- (0.01)x ]= 5415.

thus, [ 1- (0.01)x ] ²= 361/400 ⇒ 1- 0.01x = 19/20

0.01x= 1/20

hence, on solving we get x= 5

Thus, the rate at which the migration is taking place is x% i.e. 5%

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thanks!!..:)