from P a line to y axis is drawn and form Q a line parallel to x axis is drawn. both these lines intersect at the point R. if coordinates of P an Q are (3,4) and (1,-7) the coordinates of R is
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Equation of line parallel to Y axis
Thus, if P(x, y) is any point on AB, then x = a. Hence, the equation of a straight line parallel to y-axis at a distance a from it is x = a. The equation of y-axis is x = 0, since, y-axis is a parallel to itself at a distance 0 from it.
The point P=(p,q)=(3,4) and a line is drawn parallel to Y-axis.
Therefore, th equation of the line is x=p=3
Again another line is drawn parallel to X-axis through a point Q=(r,s)=(1,−7)
Therefore, the equation of the line is y=s=−7
Therefore, the lines are x=3 and y=−7
Therefore, the point of intersection is
(x,y)=(3,−7)
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