Math, asked by tenzin1704, 6 months ago

from partial fraction

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Answered by sprao53413
0

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Please see the attachment

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Answered by amankumaraman11
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 \huge \bf \frac{7 - 5x}{ {2x}^{2}  + x - 1}  \\  \\ \\   \rm  =  >  \frac{7 - 5x}{ {2x}^{2}  + 2x - x - 1}  \\  \\  \rm =  >  \frac{7 - 5x}{2x(x + 1) - 1(x + 1)}  \\  \\  \rm =  >  \frac{7 - 5x}{(2x - 1)(x + 1)}

Now, Required Partial Fractions are :

 \sf  \frac{ \red{7 - 5x}}{ \red{2x - 1}}  \:  \:  \:  \:  \:   \:  \:   \: \: \&\:  \:  \:  \:  \:  \:   \:  \: \frac{ \red{7 - 5x}}{ \red{x  + 1}}

 \\  \\  \\  \\

  • MARK BRAINLIEST
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