Question

from point outside a circle with centre o tangents pa and pb are drawn prove that aop=bop and op is perpendicular bisector of chord ab​

Answer 1

Answer:

Given : Since, the tangent at any point of a circle is perpendicular to the radius through the point of contact. ⇒ OP is the perpendicular bisector of AB. ... Since, the tangent at any point of a circle is perpendicular to the radius through the point of contact.