Question

from quadratic polynomial whose zeroes are 7+√5 and 7-√5​

Answer 1

Step-by-step explanation:

Zeroes:

$7 + \sqrt{5 } \: and \: 7 - \sqrt{5}$

sum of the zeroes:

$(7 + \sqrt{5} ) + (7 - \sqrt{5} ) \\ 7 + \sqrt{5} + 7 - \sqrt{5 } \\ 7 + 7 \\ 14$

product of zeroes:

$(7 + \sqrt{5} )(7 - \sqrt{5} ) \\ ( {7}^{2} - { \sqrt{5} }^{2} ) \\ (49 - 5) \\ 44$

General form of quadratic equation:

${x}^{2} - (sum \: of \: the \: zeroes)x + (product \: of \: the \: zeroes)$

Answer:

${x}^{2} - 14x + 44$

Answer 2

Answer:

refers to the attachment.