Question

From questio
Quel. Two numbers are in the ratio three ratio 5 if their sum is 64 then find the numbers
Que2 The sum of three consecutive multiples of five is 45 which is the smallest of the three multiples
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Answer 1

Answer:

1. two no. are in the ratio 3:5

X/Y = 3/5

= 5x =3y

5x-3y=0--------------------1

given X+ Y= 64 ---------2

X = 64-y

put it in eq 1

: 5 (64-Y)-3Y=0

320-5Y-3Y=0

320=8Y

Y = 40

hence X = 24

2. let the 3 no.s be

X-5, X , X+5

sum = 3X= 45

X =15

then the smallest multiple is 10.

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