From rest, a car accelerated at for 10 sec. The velocity of the car at the end of the 10 sec is _______________m/sec.
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1.In this case, we know the initial speed ( u=0 ), 2.the time taken ( t=10 ), the acceleration ( a=8 ), 3. we want to know the final position ( s ), so we use the following equation of motion:
we want to know the final position ( s ), so we use the following equation of motion:s=ut+12at2
we want to know the final position ( s ), so we use the following equation of motion:s=ut+12at2 ∴s=0×10+12×8×102=0+400=400
we want to know the final position ( s ), so we use the following equation of motion:s=ut+12at2 ∴s=0×10+12×8×102=0+400=400 The position of the car at the end of the 10 seconds is therefore 400m from the starting position in the direction that the acceleration was applied.
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