from sum of 2a²-3ab+b² and a²+ab+b² subtract the sum of 3a²+2ab-b² and 2a²-3ab+3b²
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Step-by-step explanation:
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Answer:
-2a²-ab
Step-by-step explanation:
First add both the equations separately,
A. 2a²-3ab+b² B. 3a²+2ab-b²
+ a²+ab+b² + 2a²-3ab+3b²
-------------------- ---------------------
3a²-2ab+2b² 5a²-ab+2b²
Now , subtract B from A
For that we need to multiply whole equation B with negative sign
that is, -(5a²-ab+2b²) = -5a²+ab-2b²
now we can directly subtract it from that
3a²-2ab+2b²
-5a²+ab-2b²
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-2a²-ab it is the required answer.
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