Math, asked by bintezulfiqar81, 9 days ago

from sum of 2a²-3ab+b² and a²+ab+b² subtract the sum of 3a²+2ab-b² and 2a²-3ab+3b²​

Answers

Answered by srivatsan100
0

Answer:

Step-by-step explanation:

Please see the attachment

Hope this will help you

Attachments:
Answered by vivekp2999
0

Answer:

-2a²-ab

Step-by-step explanation:

First add both the equations separately,

A. 2a²-3ab+b²                                              B. 3a²+2ab-b²

 +  a²+ab+b²                                                  + 2a²-3ab+3b²

   --------------------                                              ---------------------

   3a²-2ab+2b²                                                  5a²-ab+2b²

Now , subtract B from A

For that we need to multiply whole equation B with negative sign

that is, -(5a²-ab+2b²) = -5a²+ab-2b²

now we can directly subtract it from that

   3a²-2ab+2b²

  -5a²+ab-2b²

----------------------

  -2a²-ab                    it is the required answer.

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