Question

from sum of p³ + q³ - 3pq + p²q and 3p³ - q³ + 2pq + p²q subtract 3p³ - 4q³
pls send step by step answer​

Answer 1

2pq(p+q) - 3pq(p-q) = 5pq² - p²q

Step-by-step explanation:

Let first expression : 3pq(p-q),

Second expression : 2pq(p+q)

/* According to the problem given,

Subtracting first expression from second expression = 2pq(p+q) - 3pq(p-q)

= 2p²q + 2pq²-3p²q + 3pq²

= 2pq² + 3pq² + 2p²q - 3p²q

= (2+3)pq² + (2-3)p²q

= 5pq²-p²q

Therefore,

2pq(p+q) - 3pq(p-q) = 5pq² - p²q

Or

p²q² + p³-q³ + pq² + p²q

=> (3)²(-3)² + (3)³-(-3)³ + (3)(-3)² + (3)²(-3)

⇒ (9)(9) + (27)-(27) + (3)(9) + (9)(-3)

⇒ 81 + 0 + 27 + (-27)

81+0+27 - 27

⇒ 81+0

⇒ 81

मैंने आपको दो उत्तर दिए हैं। आप दोनों के बीच जो चाहें लिख सकते हैं

Answer 2

Answer:

hi

Step-by-step explanation: