Math, asked by purushotam6429, 1 year ago

From ten persons waiting in a queue, in how many ways can a selection of five be made so that (i) a specified person is always included (ii) a specified person is always excluded?126, 126124, 84124, 84120, 84

Answers

Answered by TooFree
0

Answer:

(i) 126 (ii) 126


Step-by-step explanation:

Number of people = 10


(i) Find the number of ways to choose 5 people who one specific person always included:

Number of ways = (9 x 8 x 7 x 6) / (1 x 2 x 3 x 4) = 3024/24  = 126


(ii) Find the number of ways to choose 5 people who one specific person always excluded:

Number of ways = (9 x 8 x 7 x 6 x 5) / ( 1 x 2 x 3 x 4 x 5)  = 15120/120 = 126


Answer: (i) 126 (ii) 126

Answered by Anonymous
0
HEY DEAR ... ✌️

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Here's , Your Answer :-

To find = Number of ways .

⏺️(i) A specified person is always included .

=) Number of ways = (9 x 8 x 7 x 6) / (1 x 2 x 3 x 4)

=) 3024/24  

=) 126. (ans.)


⏺️(ii) A specified person is always excluded?126, 126124, 84124, 84120, 84 .

=) Number of ways = (9 x 8 x 7 x 6 x 5) / ( 1 x 2 x 3 x 4 x 5)  

=) 15120/120

=) 126. (ans.)

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HOPE , IT HELPS ... ✌️
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