Question

From the above diagram determine
(i) The equivalent resistance of entire circuit
(ii) current through each resistors
(iii) The total current from the power supply
(iv) The voltage drop across each resistors

Answer 1

Answer:

where is diagram

Explanation:

first published diagram

Answer 2

Answer:

1. the resistor R2 and R4 are in series and R3 in parallel with series

Rs=R2 + R4

=15 + 15

=30ohm

1/Rp= 1/Rs+ 1/R3

=1/30 +1/20

=12ohm

thus effective resistance

Re=12+20+8=40ohm

thus equivalent resistance of circuit =40ohm

2.V=IR

total resistance = 40ohm

total potential difference = 12V

I=V/R

I=12/40

=0.3A

3.the current across R3=20ohm resistor is

L=V/R

=3.6/20

=0.18A

the current across R2 and R4=15ohm resistor is

L=0.3-0.18=0.12

current through R1=20ohm andR5=8ohm is 0.3A

4. the voltage drop across R1=20ohm

V=0.3*20=6V

voltage across R5=8ohm resistor is

V, 0.3*8=2.4V

voltage drop across combination of R2, R3, R4

V=0.3*12=3.6V

thus, I voltage across R3 is 3.0V

voltage across R2, R4 individually will be V=0.12*15=1.8V