Question

From the above figure, find the length of AC. Given that angleABD = 30°,
AngleADC = 45° , BD = 40m

Answer 1

Answer:

Solution



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We have , 

∠A+∠B+∠C=180∘

⇒30∘+∠B+90∘=180∘   [∵∠A=30∘and∠C=90∘]

⇒∠B=180∘−120∘=60∘

Now , cosA=ABAC

⇒cos30∘=40AC

⇒23=40AC

⇒AC=23×40⇒AC=203 units 

and , sinA=ABBC

⇒