From the adjacent figure. Find ADB
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Check the attachment.
Angle ABC is 60°
In ∆ABD
AB = BD
Now, CC is a straight line
Angle DBA + Angle ABC = 180
>> Angle DBA + 60 = 180
>> Angle DBA = 120°
Now, as ∆ABD is an isosceles triangle
Angle ADB = Angle DAB = (180-120)/2 = 60/2 = 30°
Answer : In the adjacent figure, the value of angle ADB is 30 degrees.
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