From the adjacent figure,find the area of given field.All dimensions are in meters?
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5
12200 m^2
Step-by-step explanation:
area feh is triangle so b*h/2 800/2=400m^2
area of fhjg is trapazium so (sum of parallel sides)*distance of parallel sides)/2
so (20+40)*80/2= 2400m^2
area gja = 1600m^2
are edic is rectange 80*50 = 4500M^2
area icbk is trapazium so 2400m^2
area of jba is triangle so 900m^2
adding alll we get 12200
Answered by
3
Step-by-step explanation:
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