Question

: From the adjacent figure, find the values of
i) 3 sin 0 + 4cos 0 ii) 1 - cos20
iii) sec20- tande​

Answer 1

Step-by-step explanation:

the 2nd part and the 3rd part are not clear

i mean what has been asked is not clear

please make it clear so I'll be able to help u

Answer 2

Answer:

$i) 3sinθ+4cosθ=4 \\ ii)1 - {cos}^{2} θ = \frac{576}{625}$

Step-by-step explanation:

$i) 3sinθ+4cosθ \\ </p><p>=3 \times \frac{24}{25} + 4 \times \frac{7}{25} \\ = \frac{72}{25} + \frac{28}{25} \\ = \frac{72 + 28}{25} \\ = \frac{100}{25} \\ = 4$

$ii) 1 - {cos}^{2}θ \\ </p><p>=1 - { (\frac{7}{25} )}^{2} \\ = 1 - \frac{49}{625} \\ = \frac{625 - 49}{625} \\ = \frac{576}{625}$