Question

From the adjoining figure, calculate. a) the length of PS
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Answer 1

Answer:

Given : triangle psq is right angle

x^2 + 40^2 = 41^2

x^2 + 40 × 40 = 41 × 41

x^2 + 1600 = 1681

x^2 = 1681 - 1600

x^2 = 81

x = √81

x = 9

length of ps,= 9mm

Answer 2

Answer:

The length of Ps is 9 mm

Step-by-step explanation:

GIVEN,

The length of SQ is 41 mm.

The length of PQ is 40 mm.

SINCE,SPQ is a right angled triangle .

So,using pythagoras theorem

${sq}^{2} = {pq}^{2} + {sp}^{2}$

${41}^{2} = {40}^{2} + {ps}^{2}$

${ps}^{2} = {41}^{2} - {40}^{2}$

${ps}^{2} = 1681 - 1600$

${ps}^{2} = 81$

$ps = \sqrt{81}$

$ps = 9$

Therefore, the length of ps is 9 mm