Question

from the adjoining figure find (1)the area of ABC
(2) length of BC
(3) The length of altitude from A to BC​

Answer 1

Answer:

length of bc

h^2=b^2+p^2

h^2=3^2+4^2

h^2=9+16

h^2=25

h=5cm

length of bc is 5cm

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now, area of triangle abc=1÷2×b×h

=1÷2×3×4

=6cm^2

Answer 2

Step-by-step explanation:

1)area of ABC= 1/2 × b × h

=1/2×3×4 =6cm square

2) BCsquare=ABsquare +BC square(pythagoras)

BC square =4^2+3^2

BC^2=16+9

BC^2=25

BC=5cm..

Now try to understand that...

angle A=90°

so,Ac can be the height of this traingle and when height is AC then base Is AB

but,Angle ADB is also 90°, so AD can also be the height and when height is AD, base is BC

However, area of trianle remains the same

3) 1/2× AD× BC=6

1/2×5×AD=6

AD=6×2/5 =12/5 =2.4

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