Question

From the adjoining figure, find :-

1). x
2). ANGLE DAB
3). ANGLE ADB​

Answer 1

Answer:

$(3x + 10) + (3x + 4) + (50) = 180$

$6x + 64 = 180$

$6x = 180 - 64$

$6x = 116$

$x = 116 \div 6$

$12.3$

hope helpful

Answer 2

Answer:

In ∆ADB,

∠DAB + ∠ADB + ∠DBA = 180° (Angle Sum Property)

(3x + 4)° + (3x + 10)° + 50° = 180°

3x + 4 + 3x + 10 + 50 = 180

6x + 64 = 180

6x = 180 - 64

6x = 116

x = 116/6

Now,

1. x = 116/6

2. ∠DAB = (3x + 4)° = 3×(116/6) + 4 = (116/2) + 4 = 58 + 4 = 62°

3. ∠ADB = (3x + 10)° = 3×(116/6) + 10 = (116/2) + 10 = 58 + 10 = 68°