Question

From the adjoining figure , find the distance of the
chord from the centre, if OB = 6 cm and AB = 8 cm​

Answer 1

Answer:

1 cm

Step-by-step explanation:

AB=8cm (given)

AP=28​=4cm

CD=6cm

CQ=26​=3cm

Radius OA=OC=5cm

In right angled ΔOCQ

OC2+OQ2+QC2

52=OQ2+33

OQ2=52–32

OQ2=25–9=16

OQ=4cm

In right angled ΔAOP

AO2=OP2+AP2

52=OP2+42

OP2=52–42

=25–16=9

OP=3cm

Thus, distance between two parallel lines

PQ=OQ–OP

=4–3=1cm

Thus, PQ=1cm

Answer 2

Step-by-step explanation:

Hope this was helpful to you