From the adjoining figure, find the measure of angle X and angle Y
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Answer:
Step 1
Angle y =
y + 80 = 180 (Straight line angle measures 180)
y = 180 - 100
y = 80
Step 2
Find third angle of the triangle
let third angle be ' z '
50 + y + z = 180 (All angles of triangle measures 180)
50 + 80 + z = 180
130 + z = 180
z = 180 - 130
z = 50
Step 3
x + z = 180 (Straight line angle measures 180)
x + 50 = 180
x = 180 - 50
x = 120
Answer : Angle y = 100
Angle x = 120
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Step-by-step explanation:
•From the given fig.
From the given fig.In ΔPLQ
From the given fig.In ΔPLQ∠PLQ=90
From the given fig.In ΔPLQ∠PLQ=90 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘ From the angle property
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘ From the angle property∠x=∠y
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘ From the angle property∠x=∠y⇒∠x=∠y=56
From the given fig.In ΔPLQ∠PLQ=90 ∘ ⇒∠PQL+∠PLQ+∠LPQ=180 ∘ ⇒x+90+34=180⇒x+124=180⇒x=180−124⇒x=56 ∘ From the angle property∠x=∠y⇒∠x=∠y=56 ∘
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