Question

from the adjoining figure find the values of the following
sin B
cos C
sec C
tan B + tan C

Answer 1

sin B is the value of the adjoining figure

Answer 2

Answer:

GIVEN AB = 2 CM AND AE = 3 CM (TAKE AE IS PERPENDICULAR TO AEC

NOW, BY PYTHAGORAS THEOREM

= (AB) ^2 = (AE)^2 +(BE)^2

= (AB) ^2 = ( 2 )^2 + ( 3 )^2

= AB = √4+ 9

= AB = √13

1) SIN B = 2/√13

NOW AC = ?

SO AGAIN BY PYTHAGORAS THEOREM,

= (AC) ^2 = (AE) ^2 + (BE)^2

= (AC) ^2 = ( 2 )^2 + ( 4 )^2

= AC = √4 + 16

= AC = √20

2) COS C = 4/√20

3) SEC C = √20/4

NOW NO. 4) TAN B + TAN C

= 2/3 + 2/4

= 2/3 + 1/2

= 4+3/6

= 7/6