Question

from the adjoining figures find the value of trigonometric ratios

[tan b] [tan c ] [cin b] [cos c] [cosec c]


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Answer 1

Answer:

: A right angle triangle ABC , right angled at C

AB = 10 cm

BC = 5 cm

To Find : the value of trigonometric ratios..

(a) sin B

(b) cos A

(c) tan B

(d) cos C

(e) cosec C

Solution:

AB = 10 cm

BC = 5 cm

AC² = AB² - BC²

=> AC² = 10² - 5²

=> AC² = 5²(4 - 1)

=> AC² = 5²(3)

=> AC =5√3

(a) sin B = AC/AB = 5√3/10 = √3/2

(b) cos A = AC/AB = 5√3/10 = √3/2

(c) tan B = AC/BC = 5√3/5 = √3

(d) cos C = Cos 90° = 0

(e) cosec C = 1/Sin90° = 1/1 = 1