Question

From the choices given below, choose the equation whose graph is given in figure

( 1) x+2y = 5
(2) X-2y = 5
(3) y + 2x = 5
​

Answer 1

EXPLANATION.

Equation whose graph is,

From equation (1),

⇒ p(x) = x + 2y = 5.

Put the value of x = 0 in equation, we get.

⇒ 0 + 2y = 5.

⇒ 2y = 5.

⇒ y = 2.5.

Their Co-ordinates = (0,2.5).

Put the value of y = 0 in equation, we get.

⇒ x + 2(0) = 5.

⇒ x = 5.

Their Co-ordinates = (5,0).

(2) = x - 2y = 5.

Put the value of x = 0 in equation, we get.

⇒ 0 - 2y = 5.

⇒ y = -2.5.

Their Co-ordinates = (0,-2.5).

Put y = 0 in equation, we get.

⇒ x - 2(0) = 5.

⇒ x = 5.

Their Co-ordinates = (5,0).

(3) = y + 2x = 5.

Put x = 0 in equation, we get.

⇒ y + 2(0) = 5.

⇒ y = 5.

Their Co-ordinates = (0,5).

Put y = 0 in equation, we get.

⇒ 0 + 2y = 5.

⇒ 2y = 5.

⇒ y = 2.5.

Their Co-ordinates = (2.5,0).

Answer 2

✅ First, we find coordinates of points, which are lies in the line, in both x-axis & y-axis, which represents the graph structure.

❶ x + 2y = 5

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 5 & \sf 0 \\ \\ \sf 0 & \sf 2.5 \end{array}}$

↝ For graph see the first attachment.

━─━─━─━─━─━─━─━─━─━─━─━─━─━─━

❷ x - 2y = 5

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 0 & \sf - 2.5 \\ \\ \sf 5 & \sf 0 \end{array}}$

↝ For graph see the second attachment.

━─━─━─━─━─━─━─━─━─━─━─━─━─━─━

❸ 2x + y = 5

➣ To calculate the coordinates of points, which are lies on the line, are shown in the below table.

$\boxed{\begin{array}{cccc}\bf x & \bf y \\ \frac{\qquad \qquad \qquad \qquad}{} & \frac{\qquad \qquad \qquad \qquad}{} \\ \sf 0 & \sf 5 \\ \\ \sf 2.5 & \sf 0 \end{array}}$

↝ For graph see the third attachment.