From the complete decomposition of 20g of CaCO3 at STP the volume of CO2 obtained is
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Answered by
7
Answer:
Hello mate,
Decomposition of CaCO3
⇒CaCO3=CaO+CO2
⇒1mole=1mole+1mole
⇒100gm=56gm+44gm
∴For 20gm of CaCO3
⇒20gm=11.5gm+8.8gm
but qn is to find the volume of CO2
1mole=22.4l
44gm=22.4l
8.8gm=4.48l
Hope qn is answered
Answered by
0
From the complete decomposition of 20g of CaCO3 at STP the volume of CO2 obtained is
Explanation:
Chemical reaction for the decomposition of Calcium carbonate taking place will be as follows :
→
The reaction of decomposition of calcium carbonate takes place in the presence of heat,and the product formed will be calcium oxide and carbon dioxide gas is evolved.
100 gm of on decomposition gives 22.4 litres at STP
20 gm of on decomposition will give
This value come out to be of
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