Question

From the complete decomposition of 20g of CaCO3 at STP the volume of CO2 obtained is

Answer 1

Answer:

Hello mate,

 Decomposition of CaCO3

⇒CaCO3=CaO+CO2

⇒1mole=1mole+1mole

⇒100gm=56gm+44gm  

∴For 20gm of CaCO3

⇒20gm=11.5gm+8.8gm

but qn is to find the volume of CO2

1mole=22.4l

44gm=22.4l

8.8gm=4.48l

Hope qn is answered

Answer 2

From the complete decomposition of 20g of CaCO3 at STP the volume of CO2 obtained is $4.48 litres$

Explanation:

Chemical reaction for the decomposition of Calcium carbonate taking place will be as follows :

$CaCO3$→$CaO +CO_{2}$

The reaction of decomposition of calcium carbonate takes place in the presence of heat,and the product formed will be calcium oxide and carbon dioxide gas is evolved.

100 gm of $CaCO3$ on decomposition gives 22.4 litres $CO_{2}$ at STP

20 gm of $CaCO3$ on decomposition  will give $\frac{22.4*20}{100}$

This value come out to be $4.48 litres$ of $CO_{2}$