Math, asked by jemilaangel1990, 6 months ago

From the curve y=|x| draw I)y=|x-1|+1 ii)y=|x+1|-1 iii)y=|x+2|-3​

Answers

Answered by sadafsiddqui
1

given,

y=|x|

1)y=|x-1|+1

ii)y=|x+1|-1

iii)y=|x+2|-3​

Attachments:
Answered by anjumanyasmin
1

Given:

Given, y = |x|  

If y = x

x   0  1   2

y   0  1   2

If y = -x

x   0   -1   -2

y   0    1    2

(i) y = |x – 1| + 1

y = x – 1 + 1

 y = -x + 1 + 1 = x

x   -1   0   1

y    3  2   1

(For y = 2 - x)

(ii) y = |x + 1| – 1

 y = x + 1 – 1 = x

y = -x - 1 – 1

y = -x – 2

y = – (x + 2)

x    0   1   2

y   -2  -3  4

(iii) y = |x + 2| – 3

 y = x + 2 – 3 ⇒ x – 1

y = -x – 2 + 3 = 1 – x

y = -(x – 1)

x   0   1   2   3

y   1    0  -1  -2

Attachments:
Similar questions