Question

From the data given below calculate the coefficient of variation : Karl Pearsn’s coefficient of skewness = 0.42 Arithmetic mean = 86 Mean = 80

Answer 1

$\bold{C.V= \frac{σ}{ X}×100}$

$\small \bold{\implies \: Coefficient \: of \: S_k = \frac{ \ \bar{X} - mode}{σ}}$

$\small \bold{Mode =3 \: med−2 \bar{X}=3(80)−2(86) = 68}$

$\bold{ \therefore \: 0.42= \frac{86 - 68}{σ} \implies \:σ = 42.86}$

$\bold{Coefficient \: of \: S_k=42, \bar{X}=86, Mode=68}$

$\bold{C.V. = \frac{42.86}{86} \times 100 = 49.84 \: \%}$