From the differential equation of given function is asolution.y=(X3+C)e-3x
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ans
1)
I.F. =e
∫−
x+1
1
dx
=e
−log(x+1)
=
x+1
1
The solution is
y(
x+1
1
)=∫e
3x
(x+1).
x+1
1
dx+a
⇒
x+1
y
=∫e
3x
dx+a=
3
e
3x
+a
⇒
x+1
3y
=e
3x
+c,c=3a
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