From the diffrential equation by eliminating the aribtary
constants from y2 = ax + b
Answers
Answered by
1
Step-by-step explanation:
we have y
2
=a(ax+b)
⇒y
2
=a
2
x+ab
On differentiating w.r.t x we get
2y
dx
dy
=a
2
⇒y
dx
dy
=
2
a
2
⇒y
dx
2
d
2
y
+
dx
dy
.
dx
dy
=0
y.y
2
+(y
1
)
2
=0
Hence order and degree of the given equation is 2 and 1, respectively
Answered by
0
Answer:
Differentiate the equation twice and the elliminate a and b with the help of given equation. 2y'=a
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