From the digits 4, 5, 7. 6, 1 how many three digit odd numbers can he made using each digit only once ?
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Answered by
1
You can form several numbers by keeping the odd number 5, 7, or 1 at the end so that the number formed becomes odd. Like:
647, 467, 457, 547, 657, 567, 451, 541, 761,671, 415,145.
If any doubt then comment.
Hope it helps you
647, 467, 457, 547, 657, 567, 451, 541, 761,671, 415,145.
If any doubt then comment.
Hope it helps you
manpreetgniise:
The correct answer for this question is 36. Is there any formula to solve this type of question?
No there is no formula I guess . You are which class?
And from where did you get the answer
This is DSSSB GR II's question. I am preparing for competitive exam. The answer key is given with the sample question and I think it can be solved using permutation and combination.
Ok I'm much smaller than you so I didn't know
That's fine.. Thank you anyways :)
welcome
hi
Answered by
0
457,474,451,471,461,465,467,571,561,541,517,745,751,715,761,615,617,645,675,651,671,145,157,167,165
whats your name
Manu Arora
nice
thnx
i am soahil
Nice name
which class
I am preparing for competitive exam.
well. iam 10th
can we become friends.
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