Math, asked by manpreetgniise, 1 year ago

From the digits 4, 5, 7. 6, 1 how many three digit odd numbers can he made using each digit only once ?

Answers

Answered by Jahnavidax

You can form several numbers by keeping the odd number 5, 7, or 1 at the end so that the number formed becomes odd. Like:
647, 467, 457, 547, 657, 567, 451, 541, 761,671, 415,145.
If any doubt then comment.
Hope it helps you

manpreetgniise: The correct answer for this question is 36. Is there any formula to solve this type of question?

Jahnavidax: No there is no formula I guess . You are which class?

Jahnavidax: And from where did you get the answer

manpreetgniise: This is DSSSB GR II's question. I am preparing for competitive exam. The answer key is given with the sample question and I think it can be solved using permutation and combination.

Jahnavidax: Ok I'm much smaller than you so I didn't know

manpreetgniise: That's fine.. Thank you anyways :)

Jahnavidax: welcome

Anonymous: hi

Answered by Anonymous

457,474,451,471,461,465,467,571,561,541,517,745,751,715,761,615,617,645,675,651,671,145,157,167,165

Anonymous: whats your name

manpreetgniise: Manu Arora

Anonymous: nice

manpreetgniise: thnx

Anonymous: i am soahil

manpreetgniise: Nice name

Anonymous: which class

manpreetgniise: I am preparing for competitive exam.

Anonymous: well. iam 10th

Anonymous: can we become friends.

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