Question

From the equation it is clear that one mole of Ammonia reacts with one mole of HCl to form one mole of Ammonium chloride, then the mass of HCl required to react with 10 g Ammonia to give NH4Cl will be:
(A)2.147 g (B) 21.47 g (C)214.7 g (D) 2.547 g

Answer 1

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Here's ur answer

NH₃ + HCl ------> NH₄Cl

1 mole NH₃ => 1 mole HCl

Number of moles of NH₃ = Given mass/Molar mass

                                            = 10/17 moles

Hence,

10/17 moles NH₃ => 10/17 moles HCl

Number of moles of HCl = Given mass/Molar mass

10/17 = Given mass/36.5

Given mass = 21.47g

Hence, option (C) is the coorect answer

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