Question

from the equation whose roots are (-3+5i,-3-5i)​

Answer 1

Answer:

0 is the answer

Step-by-step explanation:

What is the quadratic equation whose roots are 3 + 5i and 3 - 5i?

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If (x+a)(x+b)=0,

then -a and -b are the roots of the equation.

So let -a=3+5i, and -b=3–5i,

therefore a=-(3+5i)=-3–5i.

and b=-(3–5i)=5i-3

therefore (x+a)(x+b)=0

{x+(-3–5i)}(x+5i-3)=0

(x-3–5i)(x+5i-3)=0

x square+x(-3–5i)+x(5i-3)+(-3–5i)(5i-3)=0

x square+x(-3–5i+5i-3)+{-15i+9-25(i square)+15i}=0

x square-9x+{-15i+9-25(-1)+15i}=0

x square-9x+(9+25)=0

x square-9x+34=0

Therfore a quadratic equation whose roots are 3+5i and 3–5i is:

x square-9x+34=0