Question

from the equation whose roots are the cubes of the roots of x³+3x²+2=0​

Answer 1

Answer:

x3+33x2+12x+8=0

Step-by-step explanation:

Let y=x 3

x3+3x 2 +2=0

⇒x 3 +2=−3x 2

⇒(x 3+2) 3 =(−3x 2 ) 3

⇒x9+8+3x 32(x3+2)=−27x 6

⇒x9+6x 6+12x3+8=−27x6

⇒x9+33x6+12x3+8=0

Substituting y=x3

, we get

y3+33y 2+12y+8=0

Now replacing y by x

x 3+33x 2+12x+8=0 is the required equation.

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