Question

From the fig 14 In ABC ,A = 50°, B = 70° and the bisector of  C meets AB in D (fig ) .Measure ADC

Answer 1

Answer:

100°

Step-by-step explanation:

in triangle ABC

angle A+B+C=180°

50°+70°+C=180°

C = 180-120

C = 60°

now CD is bisector of angle C

angle ACD=1/2 of 60°

=30°

now in triangle ACD

angle A+C+D=180°

50°+30°+D=180°

D = 180°-80°

D = 100°

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